Vs=10 & 15 volts, R=1 kohm, 1 x Zener diode, 1 x diode
Zd=5.1 volts
D=0.7 volts
----------------At 10 volts------------------------------At 15 volts
Volt drop V1=4.68 volts_______________________4.83 volts
Volt drop V2=0.67 volts_______________________0.69 volts
Volt drop V3=5.34 volts_______________________5.52 volts
Volt drop V4=5.22 volts_______________________9.83 volts
Current amps at 10 volts Vs
I=V/R=(10-5.1-0.7)/1000=4.2 mili amps
Current amps at 15 volts Vs
I=V/R=(15-5.1-0.7)/1000=9.2 mili volts
When zener diode installed in reverse bias it takes 5.1 volts to run and let the rest through and another diode installed in forward bias, takes 0.7 volts to run and let the rest through so voltage drop across two diodes would be 5.1+0.7=5.8 volts, it doest matter how much voltage applied as they will act with the same voltage drop, until voltage would be so high it just push thorough the diodes and damage them.
Voltage drop across resistor indicates how much voltage let for it to use.
Good explanation on the operation of the two diodes but what is happening with the resistor?
ReplyDeletewhy is its reading changing?